-(9x-2)=9+5(1-3x)

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Solution for -(9x-2)=9+5(1-3x) equation: 



-(9x-2)=9+5(1-3x)

We move all terms to the left:

-(9x-2)-(9+5(1-3x))=0

We add all the numbers together, and all the variables

-(9x-2)-(9+5(-3x+1))=0

We get rid of parentheses

-9x-(9+5(-3x+1))+2=0



We calculate terms in parentheses: -(9+5(-3x+1)), so:

9+5(-3x+1)

determiningTheFunctionDomain
5(-3x+1)+9

We multiply parentheses

-15x+5+9

We add all the numbers together, and all the variables

-15x+14

Back to the equation:

-(-15x+14)



We get rid of parentheses

-9x+15x-14+2=0

We add all the numbers together, and all the variables

6x-12=0

We move all terms containing x to the left, all other terms to the right

6x=12

x=12/6

x=2

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