(2x)+(3x)+(3x+12)=180

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Solution for (2x)+(3x)+(3x+12)=180 equation: 



(2x)+(3x)+(3x+12)=180

We move all terms to the left:

(2x)+(3x)+(3x+12)-(180)=0

We add all the numbers together, and all the variables

5x+(3x+12)-180=0

We get rid of parentheses

5x+3x+12-180=0

We add all the numbers together, and all the variables

8x-168=0

We move all terms containing x to the left, all other terms to the right

8x=168

x=168/8

x=21

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