-(8x-2)=3+10(1+3x)

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Solution for -(8x-2)=3+10(1+3x) equation: 



-(8x-2)=3+10(1+3x)

We move all terms to the left:

-(8x-2)-(3+10(1+3x))=0

We add all the numbers together, and all the variables

-(8x-2)-(3+10(3x+1))=0

We get rid of parentheses

-8x-(3+10(3x+1))+2=0



We calculate terms in parentheses: -(3+10(3x+1)), so:

3+10(3x+1)

determiningTheFunctionDomain
10(3x+1)+3

We multiply parentheses

30x+10+3

We add all the numbers together, and all the variables

30x+13

Back to the equation:

-(30x+13)



We get rid of parentheses

-8x-30x-13+2=0

We add all the numbers together, and all the variables

-38x-11=0

We move all terms containing x to the left, all other terms to the right

-38x=11

x=11/-38

x=-11/38

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