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8y+6-2(-2y-2)=2(y-4)
We move all terms to the left:
8y+6-2(-2y-2)-(2(y-4))=0
We multiply parentheses
8y+4y-(2(y-4))+4+6=0
We calculate terms in parentheses: -(2(y-4)), so:We add all the numbers together, and all the variables
2(y-4)
We multiply parentheses
2y-8
Back to the equation:
-(2y-8)
12y-(2y-8)+10=0
We get rid of parentheses
12y-2y+8+10=0
We add all the numbers together, and all the variables
10y+18=0
We move all terms containing y to the left, all other terms to the right
10y=-18
y=-18/10
y=-1+4/5
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