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-(6-2x)+6=2(x-5)
We move all terms to the left:
-(6-2x)+6-(2(x-5))=0
We add all the numbers together, and all the variables
-(-2x+6)-(2(x-5))+6=0
We get rid of parentheses
2x-(2(x-5))-6+6=0
We calculate terms in parentheses: -(2(x-5)), so:We add all the numbers together, and all the variables
2(x-5)
We multiply parentheses
2x-10
Back to the equation:
-(2x-10)
2x-(2x-10)=0
We get rid of parentheses
2x-2x+10=0
We add all the numbers together, and all the variables
10!=0
There is no solution for this equation
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