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-(5/3)h=6
We move all terms to the left:
-(5/3)h-(6)=0
Domain of the equation: 3)h!=0We add all the numbers together, and all the variables
h!=0/1
h!=0
h∈R
-(+5/3)h-6=0
We multiply parentheses
-5h^2-6=0
a = -5; b = 0; c = -6;
Δ = b2-4ac
Δ = 02-4·(-5)·(-6)
Δ = -120
Delta is less than zero, so there is no solution for the equation
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