20-3+10y-4=-5(3y-4)-5(y-1)-9y+12

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Solution for 20-3+10y-4=-5(3y-4)-5(y-1)-9y+12 equation:



20-3+10y-4=-5(3y-4)-5(y-1)-9y+12
We move all terms to the left:
20-3+10y-4-(-5(3y-4)-5(y-1)-9y+12)=0
We add all the numbers together, and all the variables
10y-(-5(3y-4)-5(y-1)-9y+12)+13=0
We calculate terms in parentheses: -(-5(3y-4)-5(y-1)-9y+12), so:
-5(3y-4)-5(y-1)-9y+12
We add all the numbers together, and all the variables
-9y-5(3y-4)-5(y-1)+12
We multiply parentheses
-9y-15y-5y+20+5+12
We add all the numbers together, and all the variables
-29y+37
Back to the equation:
-(-29y+37)
We get rid of parentheses
10y+29y-37+13=0
We add all the numbers together, and all the variables
39y-24=0
We move all terms containing y to the left, all other terms to the right
39y=24
y=24/39
y=8/13

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