-(4z-3)+1=4-(4z+2)

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Solution for -(4z-3)+1=4-(4z+2) equation: 



-(4z-3)+1=4-(4z+2)

We move all terms to the left:

-(4z-3)+1-(4-(4z+2))=0

We get rid of parentheses

-4z-(4-(4z+2))+3+1=0



We calculate terms in parentheses: -(4-(4z+2)), so:

4-(4z+2)

determiningTheFunctionDomain
-(4z+2)+4

We get rid of parentheses

-4z-2+4

We add all the numbers together, and all the variables

-4z+2

Back to the equation:

-(-4z+2)



We add all the numbers together, and all the variables

-4z-(-4z+2)+4=0

We get rid of parentheses

-4z+4z-2+4=0

We add all the numbers together, and all the variables

2!=0

There is no solution for this equation

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