-(4c-7)=5c+(11-7c)

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Solution for -(4c-7)=5c+(11-7c) equation: 



-(4c-7)=5c+(11-7c)

We move all terms to the left:

-(4c-7)-(5c+(11-7c))=0

We add all the numbers together, and all the variables

-(4c-7)-(5c+(-7c+11))=0

We get rid of parentheses

-4c-(5c+(-7c+11))+7=0



We calculate terms in parentheses: -(5c+(-7c+11)), so:

5c+(-7c+11)

We get rid of parentheses

5c-7c+11

We add all the numbers together, and all the variables

-2c+11

Back to the equation:

-(-2c+11)



We get rid of parentheses

-4c+2c-11+7=0

We add all the numbers together, and all the variables

-2c-4=0

We move all terms containing c to the left, all other terms to the right

-2c=4

c=4/-2

c=-2

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