(9-2b)-(b+5)=16

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Solution for (9-2b)-(b+5)=16 equation: 



(9-2b)-(b+5)=16

We move all terms to the left:

(9-2b)-(b+5)-(16)=0

We add all the numbers together, and all the variables

(-2b+9)-(b+5)-16=0

We get rid of parentheses

-2b-b+9-5-16=0

We add all the numbers together, and all the variables

-3b-12=0

We move all terms containing b to the left, all other terms to the right

-3b=12

b=12/-3

b=-4

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