-(4-2n)=2n+2(n-5)

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Solution for -(4-2n)=2n+2(n-5) equation: 



-(4-2n)=2n+2(n-5)

We move all terms to the left:

-(4-2n)-(2n+2(n-5))=0

We add all the numbers together, and all the variables

-(-2n+4)-(2n+2(n-5))=0

We get rid of parentheses

2n-(2n+2(n-5))-4=0



We calculate terms in parentheses: -(2n+2(n-5)), so:

2n+2(n-5)

We multiply parentheses

2n+2n-10

We add all the numbers together, and all the variables

4n-10

Back to the equation:

-(4n-10)



We get rid of parentheses

2n-4n+10-4=0

We add all the numbers together, and all the variables

-2n+6=0

We move all terms containing n to the left, all other terms to the right

-2n=-6

n=-6/-2

n=+3

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