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2y+1/3y-5=0
Domain of the equation: 3y!=0We multiply all the terms by the denominator
y!=0/3
y!=0
y∈R
2y*3y-5*3y+1=0
Wy multiply elements
6y^2-15y+1=0
a = 6; b = -15; c = +1;
Δ = b2-4ac
Δ = -152-4·6·1
Δ = 201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{201}}{2*6}=\frac{15-\sqrt{201}}{12} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{201}}{2*6}=\frac{15+\sqrt{201}}{12} $
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