-(4+3b)+6b=6+4(1+b)

Solution for -(4+3b)+6b=6+4(1+b) equation:

-(4+3b)+6b=6+4(1+b)

We move all terms to the left:

-(4+3b)+6b-(6+4(1+b))=0

We add all the numbers together, and all the variables

-(3b+4)+6b-(6+4(b+1))=0

We add all the numbers together, and all the variables

6b-(3b+4)-(6+4(b+1))=0

We get rid of parentheses

6b-3b-(6+4(b+1))-4=0


We calculate terms in parentheses: -(6+4(b+1)), so:

6+4(b+1)

determiningTheFunctionDomain
4(b+1)+6

We multiply parentheses

4b+4+6

We add all the numbers together, and all the variables

4b+10

Back to the equation:

-(4b+10)


We add all the numbers together, and all the variables

3b-(4b+10)-4=0

We get rid of parentheses

3b-4b-10-4=0

We add all the numbers together, and all the variables

-1b-14=0

We move all terms containing b to the left, all other terms to the right

-b=14

b=14/-1

b=-14