74+2y=2(3y+2)+2(2y+3)

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Solution for 74+2y=2(3y+2)+2(2y+3) equation: 



74+2y=2(3y+2)+2(2y+3)

We move all terms to the left:

74+2y-(2(3y+2)+2(2y+3))=0



We calculate terms in parentheses: -(2(3y+2)+2(2y+3)), so:

2(3y+2)+2(2y+3)

We multiply parentheses

6y+4y+4+6

We add all the numbers together, and all the variables

10y+10

Back to the equation:

-(10y+10)



We get rid of parentheses

2y-10y-10+74=0

We add all the numbers together, and all the variables

-8y+64=0

We move all terms containing y to the left, all other terms to the right

-8y=-64

y=-64/-8

y=+8

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