-(4+2b)=4(b-2)

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Solution for -(4+2b)=4(b-2) equation: 



-(4+2b)=4(b-2)

We move all terms to the left:

-(4+2b)-(4(b-2))=0

We add all the numbers together, and all the variables

-(2b+4)-(4(b-2))=0

We get rid of parentheses

-2b-(4(b-2))-4=0



We calculate terms in parentheses: -(4(b-2)), so:

4(b-2)

We multiply parentheses

4b-8

Back to the equation:

-(4b-8)



We get rid of parentheses

-2b-4b+8-4=0

We add all the numbers together, and all the variables

-6b+4=0

We move all terms containing b to the left, all other terms to the right

-6b=-4

b=-4/-6

b=2/3

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