4(v+3)=2(v-4)

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Solution for 4(v+3)=2(v-4) equation: 



4(v+3)=2(v-4)

We move all terms to the left:

4(v+3)-(2(v-4))=0

We multiply parentheses

4v-(2(v-4))+12=0



We calculate terms in parentheses: -(2(v-4)), so:

2(v-4)

We multiply parentheses

2v-8

Back to the equation:

-(2v-8)



We get rid of parentheses

4v-2v+8+12=0

We add all the numbers together, and all the variables

2v+20=0

We move all terms containing v to the left, all other terms to the right

2v=-20

v=-20/2

v=-10

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