-(3x-4)+2(x+3)=-2x+2(x+14)

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Solution for -(3x-4)+2(x+3)=-2x+2(x+14) equation:



-(3x-4)+2(x+3)=-2x+2(x+14)
We move all terms to the left:
-(3x-4)+2(x+3)-(-2x+2(x+14))=0
We multiply parentheses
-(3x-4)+2x-(-2x+2(x+14))+6=0
We get rid of parentheses
-3x+2x-(-2x+2(x+14))+4+6=0
We calculate terms in parentheses: -(-2x+2(x+14)), so:
-2x+2(x+14)
We multiply parentheses
-2x+2x+28
We add all the numbers together, and all the variables
28
Back to the equation:
-(28)
We add all the numbers together, and all the variables
-1x-18=0
We move all terms containing x to the left, all other terms to the right
-x=18
x=18/-1
x=-18

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