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10(2x-4)+5(x+5)=-5(-x-9)
We move all terms to the left:
10(2x-4)+5(x+5)-(-5(-x-9))=0
We add all the numbers together, and all the variables
10(2x-4)+5(x+5)-(-5(-1x-9))=0
We multiply parentheses
20x+5x-(-5(-1x-9))-40+25=0
We calculate terms in parentheses: -(-5(-1x-9)), so:We add all the numbers together, and all the variables
-5(-1x-9)
We multiply parentheses
5x+45
Back to the equation:
-(5x+45)
25x-(5x+45)-15=0
We get rid of parentheses
25x-5x-45-15=0
We add all the numbers together, and all the variables
20x-60=0
We move all terms containing x to the left, all other terms to the right
20x=60
x=60/20
x=3
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