-(3x+5)(2x-1)=20x(x-2)+27

Solution for -(3x+5)(2x-1)=20x(x-2)+27 equation:

-(3x+5)(2x-1)=20x(x-2)+27

We move all terms to the left:

-(3x+5)(2x-1)-(20x(x-2)+27)=0

We multiply parentheses ..

-(+6x^2-3x+10x-5)-(20x(x-2)+27)=0


We calculate terms in parentheses: -(20x(x-2)+27), so:

20x(x-2)+27

We multiply parentheses

20x^2-40x+27

Back to the equation:

-(20x^2-40x+27)


We get rid of parentheses

-6x^2-20x^2+3x-10x+40x+5-27=0

We add all the numbers together, and all the variables

-26x^2+33x-22=0

a = -26; b = 33; c = -22;
Δ = b2-4ac
Δ = 332-4·(-26)·(-22)
Δ = -1199
Delta is less than zero, so there is no solution for the equation