4(3x-5)=12-2(x+8)

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Solution for 4(3x-5)=12-2(x+8) equation: 



4(3x-5)=12-2(x+8)

We move all terms to the left:

4(3x-5)-(12-2(x+8))=0

We multiply parentheses

12x-(12-2(x+8))-20=0



We calculate terms in parentheses: -(12-2(x+8)), so:

12-2(x+8)

determiningTheFunctionDomain
-2(x+8)+12

We multiply parentheses

-2x-16+12

We add all the numbers together, and all the variables

-2x-4

Back to the equation:

-(-2x-4)



We get rid of parentheses

12x+2x+4-20=0

We add all the numbers together, and all the variables

14x-16=0

We move all terms containing x to the left, all other terms to the right

14x=16

x=16/14

x=1+1/7

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