-(3/2)(d-2)=21

Solution for -(3/2)(d-2)=21 equation:

-(3/2)(d-2)=21

We move all terms to the left:

-(3/2)(d-2)-(21)=0


Domain of the equation: 2)(d-2)!=0

d∈R


We add all the numbers together, and all the variables

-(+3/2)(d-2)-21=0

We multiply parentheses ..

-(+3d^2+3/2*-2)-21=0

We multiply all the terms by the denominator


-(+3d^2+3-21*2*-2)=0

We get rid of parentheses

-3d^2-3+2+21*2*=0

We add all the numbers together, and all the variables

-3d^2=0

a = -3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-3)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$d=\frac{-b}{2a}=\frac{0}{-6}=0$