-(2d+5)=-3d+2(2d-5)

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Solution for -(2d+5)=-3d+2(2d-5) equation: 



-(2d+5)=-3d+2(2d-5)

We move all terms to the left:

-(2d+5)-(-3d+2(2d-5))=0

We get rid of parentheses

-2d-(-3d+2(2d-5))-5=0



We calculate terms in parentheses: -(-3d+2(2d-5)), so:

-3d+2(2d-5)

We multiply parentheses

-3d+4d-10

We add all the numbers together, and all the variables

d-10

Back to the equation:

-(d-10)



We get rid of parentheses

-2d-d+10-5=0

We add all the numbers together, and all the variables

-3d+5=0

We move all terms containing d to the left, all other terms to the right

-3d=-5

d=-5/-3

d=1+2/3

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