5(x+2)-1=10x-(23-2x)

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Solution for 5(x+2)-1=10x-(23-2x) equation: 



5(x+2)-1=10x-(23-2x)

We move all terms to the left:

5(x+2)-1-(10x-(23-2x))=0

We add all the numbers together, and all the variables

5(x+2)-(10x-(-2x+23))-1=0

We multiply parentheses

5x-(10x-(-2x+23))+10-1=0



We calculate terms in parentheses: -(10x-(-2x+23)), so:

10x-(-2x+23)

We get rid of parentheses

10x+2x-23

We add all the numbers together, and all the variables

12x-23

Back to the equation:

-(12x-23)



We add all the numbers together, and all the variables

5x-(12x-23)+9=0

We get rid of parentheses

5x-12x+23+9=0

We add all the numbers together, and all the variables

-7x+32=0

We move all terms containing x to the left, all other terms to the right

-7x=-32

x=-32/-7

x=4+4/7

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