-(20c-50)=-3c-5+38c

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Solution for -(20c-50)=-3c-5+38c equation: 



-(20c-50)=-3c-5+38c

We move all terms to the left:

-(20c-50)-(-3c-5+38c)=0

We add all the numbers together, and all the variables

-(20c-50)-(35c-5)=0

We get rid of parentheses

-20c-35c+50+5=0

We add all the numbers together, and all the variables

-55c+55=0

We move all terms containing c to the left, all other terms to the right

-55c=-55

c=-55/-55

c=1

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