2(5x2)=2+15

Solution for 2(5x2)=2+15 equation:

2(5x^2)=2+15

We move all terms to the left:

2(5x^2)-(2+15)=0

We add all the numbers together, and all the variables

25x^2-17=0

a = 25; b = 0; c = -17;
Δ = b2-4ac
Δ = 02-4·25·(-17)
Δ = 1700
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1700}=\sqrt{100*17}=\sqrt{100}*\sqrt{17}=10\sqrt{17}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{17}}{2*25}=\frac{0-10\sqrt{17}}{50}
=-\frac{10\sqrt{17}}{50}
=-\frac{\sqrt{17}}{5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{17}}{2*25}=\frac{0+10\sqrt{17}}{50}
=\frac{10\sqrt{17}}{50}
=\frac{\sqrt{17}}{5}
$