-(2+5)+(6z+1)=3(z-1)

Solution for -(2+5)+(6z+1)=3(z-1) equation:

Simplifying
-1(2 + 5) + (6z + 1) = 3(z + -1)

Combine like terms: 2 + 5 = 7
-1(7) + (6z + 1) = 3(z + -1)

Multiply -1 * 7
-7 + (6z + 1) = 3(z + -1)

Reorder the terms:
-7 + (1 + 6z) = 3(z + -1)

Remove parenthesis around (1 + 6z)
-7 + 1 + 6z = 3(z + -1)

Combine like terms: -7 + 1 = -6
-6 + 6z = 3(z + -1)

Reorder the terms:
-6 + 6z = 3(-1 + z)
-6 + 6z = (-1 * 3 + z * 3)
-6 + 6z = (-3 + 3z)

Solving
-6 + 6z = -3 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-6 + 6z + -3z = -3 + 3z + -3z

Combine like terms: 6z + -3z = 3z
-6 + 3z = -3 + 3z + -3z

Combine like terms: 3z + -3z = 0
-6 + 3z = -3 + 0
-6 + 3z = -3

Add '6' to each side of the equation.
-6 + 6 + 3z = -3 + 6

Combine like terms: -6 + 6 = 0
0 + 3z = -3 + 6
3z = -3 + 6

Combine like terms: -3 + 6 = 3
3z = 3

Divide each side by '3'.
z = 1

Simplifying
z = 1