-(2+5)+(6z+1)=3(2-1)

Solution for -(2+5)+(6z+1)=3(2-1) equation:

Simplifying
-1(2 + 5) + (6z + 1) = 3(2 + -1)

Combine like terms: 2 + 5 = 7
-1(7) + (6z + 1) = 3(2 + -1)

Multiply -1 * 7
-7 + (6z + 1) = 3(2 + -1)

Reorder the terms:
-7 + (1 + 6z) = 3(2 + -1)

Remove parenthesis around (1 + 6z)
-7 + 1 + 6z = 3(2 + -1)

Combine like terms: -7 + 1 = -6
-6 + 6z = 3(2 + -1)

Combine like terms: 2 + -1 = 1
-6 + 6z = 3(1)

Multiply 3 * 1
-6 + 6z = 3

Solving
-6 + 6z = 3

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + 6z = 3 + 6

Combine like terms: -6 + 6 = 0
0 + 6z = 3 + 6
6z = 3 + 6

Combine like terms: 3 + 6 = 9
6z = 9

Divide each side by '6'.
z = 1.5

Simplifying
z = 1.5