-(1/6)(x-12)+(1/2)(x+2)=x-1

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Solution for -(1/6)(x-12)+(1/2)(x+2)=x-1 equation: 



-(1/6)(x-12)+(1/2)(x+2)=x-1

We move all terms to the left:

-(1/6)(x-12)+(1/2)(x+2)-(x-1)=0



Domain of the equation: 6)(x-12)!=0

x∈R





Domain of the equation: 2)(x+2)!=0

x∈R



We add all the numbers together, and all the variables

-(+1/6)(x-12)+(+1/2)(x+2)-(x-1)=0

We get rid of parentheses

-(+1/6)(x-12)+(+1/2)(x+2)-x+1=0

We multiply parentheses ..

-(+x^2+1/6*-12)+(+1/2)(x+2)-x+1=0

We calculate fractions

There is no solution for this equation

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