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4x+2(x-3)=4x-2(x-5)+8
We move all terms to the left:
4x+2(x-3)-(4x-2(x-5)+8)=0
We multiply parentheses
4x+2x-(4x-2(x-5)+8)-6=0
We calculate terms in parentheses: -(4x-2(x-5)+8), so:We add all the numbers together, and all the variables
4x-2(x-5)+8
We multiply parentheses
4x-2x+10+8
We add all the numbers together, and all the variables
2x+18
Back to the equation:
-(2x+18)
6x-(2x+18)-6=0
We get rid of parentheses
6x-2x-18-6=0
We add all the numbers together, and all the variables
4x-24=0
We move all terms containing x to the left, all other terms to the right
4x=24
x=24/4
x=6
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