-(1/2)x+2=10

Solution for -(1/2)x+2=10 equation:

-(1/2)x+2=10

We move all terms to the left:

-(1/2)x+2-(10)=0


Domain of the equation: 2)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-(+1/2)x+2-10=0

We add all the numbers together, and all the variables

-(+1/2)x-8=0

We multiply parentheses

-x^2-8=0

We add all the numbers together, and all the variables

-1x^2-8=0

a = -1; b = 0; c = -8;
Δ = b2-4ac
Δ = 02-4·(-1)·(-8)
Δ = -32
Delta is less than zero, so there is no solution for the equation