-(1/2)m=-9

Solution for -(1/2)m=-9 equation:

-(1/2)m=-9

We move all terms to the left:

-(1/2)m-(-9)=0


Domain of the equation: 2)m!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

-(+1/2)m-(-9)=0

We add all the numbers together, and all the variables

-(+1/2)m+9=0

We multiply parentheses

-m^2+9=0

We add all the numbers together, and all the variables

-1m^2+9=0

a = -1; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·(-1)·9
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6}{2*-1}=\frac{-6}{-2}
=+3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6}{2*-1}=\frac{6}{-2}
=-3
$