(7x-10)+(3x-12)=138

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Solution for (7x-10)+(3x-12)=138 equation: 



(7x-10)+(3x-12)=138

We move all terms to the left:

(7x-10)+(3x-12)-(138)=0

We get rid of parentheses

7x+3x-10-12-138=0

We add all the numbers together, and all the variables

10x-160=0

We move all terms containing x to the left, all other terms to the right

10x=160

x=160/10

x=16

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