-(1+7x)-6(-7-x)+36x=2

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Solution for -(1+7x)-6(-7-x)+36x=2 equation: 



-(1+7x)-6(-7-x)+36x=2

We move all terms to the left:

-(1+7x)-6(-7-x)+36x-(2)=0

We add all the numbers together, and all the variables

-(7x+1)-6(-1x-7)+36x-2=0

We add all the numbers together, and all the variables

36x-(7x+1)-6(-1x-7)-2=0

We multiply parentheses

36x-(7x+1)+6x+42-2=0

We get rid of parentheses

36x-7x+6x-1+42-2=0

We add all the numbers together, and all the variables

35x+39=0

We move all terms containing x to the left, all other terms to the right

35x=-39

x=-39/35

x=-1+4/35

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