2x(x-3x)=-36-4x

Solution for 2x(x-3x)=-36-4x equation:

2x(x-3x)=-36-4x

We move all terms to the left:

2x(x-3x)-(-36-4x)=0

We add all the numbers together, and all the variables

2x(-2x)-(-4x-36)=0

We multiply parentheses

-4x^2-(-4x-36)=0

We get rid of parentheses

-4x^2+4x+36=0

a = -4; b = 4; c = +36;
Δ = b2-4ac
Δ = 42-4·(-4)·36
Δ = 592
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{592}=\sqrt{16*37}=\sqrt{16}*\sqrt{37}=4\sqrt{37}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{37}}{2*-4}=\frac{-4-4\sqrt{37}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{37}}{2*-4}=\frac{-4+4\sqrt{37}}{-8}
$