-(-x-5)=x-2+2(x-12)

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Solution for -(-x-5)=x-2+2(x-12) equation: 



-(-x-5)=x-2+2(x-12)

We move all terms to the left:

-(-x-5)-(x-2+2(x-12))=0

We add all the numbers together, and all the variables

-(-1x-5)-(x-2+2(x-12))=0

We get rid of parentheses

1x-(x-2+2(x-12))+5=0



We calculate terms in parentheses: -(x-2+2(x-12)), so:

x-2+2(x-12)

determiningTheFunctionDomain
x+2(x-12)-2

We multiply parentheses

x+2x-24-2

We add all the numbers together, and all the variables

3x-26

Back to the equation:

-(3x-26)



We add all the numbers together, and all the variables

x-(3x-26)+5=0

We get rid of parentheses

x-3x+26+5=0

We add all the numbers together, and all the variables

-2x+31=0

We move all terms containing x to the left, all other terms to the right

-2x=-31

x=-31/-2

x=15+1/2

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