3(30+n)=49(n+19)

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Solution for 3(30+n)=49(n+19) equation: 



3(30+n)=49(n+19)

We move all terms to the left:

3(30+n)-(49(n+19))=0

We add all the numbers together, and all the variables

3(n+30)-(49(n+19))=0

We multiply parentheses

3n-(49(n+19))+90=0



We calculate terms in parentheses: -(49(n+19)), so:

49(n+19)

We multiply parentheses

49n+931

Back to the equation:

-(49n+931)



We get rid of parentheses

3n-49n-931+90=0

We add all the numbers together, and all the variables

-46n-841=0

We move all terms containing n to the left, all other terms to the right

-46n=841

n=841/-46

n=-18+13/46

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