-(-2+3b)=-3-(b-3)

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Solution for -(-2+3b)=-3-(b-3) equation: 



-(-2+3b)=-3-(b-3)

We move all terms to the left:

-(-2+3b)-(-3-(b-3))=0

We add all the numbers together, and all the variables

-(3b-2)-(-3-(b-3))=0

We get rid of parentheses

-3b-(-3-(b-3))+2=0



We calculate terms in parentheses: -(-3-(b-3)), so:

-3-(b-3)

determiningTheFunctionDomain
-(b-3)-3

We get rid of parentheses

-b+3-3

We add all the numbers together, and all the variables

-b

Back to the equation:

-(-b)



We add all the numbers together, and all the variables

-3b-(-1b)+2=0

We get rid of parentheses

-3b+1b+2=0

We add all the numbers together, and all the variables

-2b+2=0

We move all terms containing b to the left, all other terms to the right

-2b=-2

b=-2/-2

b=1

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