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.5t^2-7t-60=0
a = .5; b = -7; c = -60;
Δ = b2-4ac
Δ = -72-4·.5·(-60)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-13}{2*.5}=\frac{-6}{1} =-6 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+13}{2*.5}=\frac{20}{1} =20 $
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