+24x2=38

Solution for +24x2=38 equation:

+24x^2=38

We move all terms to the left:

+24x^2-(38)=0

a = 24; b = 0; c = -38;
Δ = b2-4ac
Δ = 02-4·24·(-38)
Δ = 3648
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3648}=\sqrt{64*57}=\sqrt{64}*\sqrt{57}=8\sqrt{57}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{57}}{2*24}=\frac{0-8\sqrt{57}}{48}
=-\frac{8\sqrt{57}}{48}
=-\frac{\sqrt{57}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{57}}{2*24}=\frac{0+8\sqrt{57}}{48}
=\frac{8\sqrt{57}}{48}
=\frac{\sqrt{57}}{6}
$