+2(-2x+3)3+(x-2)=13-2(x-2)

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Solution for +2(-2x+3)3+(x-2)=13-2(x-2) equation: 



+2(-2x+3)3+(x-2)=13-2(x-2)

We move all terms to the left:

+2(-2x+3)3+(x-2)-(13-2(x-2))=0

We multiply parentheses

-12x+(x-2)-(13-2(x-2))+18=0

We get rid of parentheses

-12x+x-(13-2(x-2))-2+18=0



We calculate terms in parentheses: -(13-2(x-2)), so:

13-2(x-2)

determiningTheFunctionDomain
-2(x-2)+13

We multiply parentheses

-2x+4+13

We add all the numbers together, and all the variables

-2x+17

Back to the equation:

-(-2x+17)



We add all the numbers together, and all the variables

-11x-(-2x+17)+16=0

We get rid of parentheses

-11x+2x-17+16=0

We add all the numbers together, and all the variables

-9x-1=0

We move all terms containing x to the left, all other terms to the right

-9x=1

x=1/-9

x=-1/9

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