7(2-m)m=3m

Solution for 7(2-m)m=3m equation:

7(2-m)m=3m

We move all terms to the left:

7(2-m)m-(3m)=0

We add all the numbers together, and all the variables

7(-1m+2)m-3m=0

We add all the numbers together, and all the variables

-3m+7(-1m+2)m=0

We multiply parentheses

-7m^2-3m+14m=0

We add all the numbers together, and all the variables

-7m^2+11m=0

a = -7; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·(-7)·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*-7}=\frac{-22}{-14}
=1+4/7
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*-7}=\frac{0}{-14}
=0
$