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)x(6x-2)+5=6x(x-5)+x
We move all terms to the left:
)x(6x-2)+5-(6x(x-5)+x)=0
We calculate terms in parentheses: -(6x(x-5)+x), so:We get rid of parentheses
6x(x-5)+x
We add all the numbers together, and all the variables
x+6x(x-5)
We multiply parentheses
6x^2+x-30x
We add all the numbers together, and all the variables
6x^2-29x
Back to the equation:
-(6x^2-29x)
-2)-6x^2+29x+5+)x(6x=0
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