(z+9)/3=(z-9)/2

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Solution for (z+9)/3=(z-9)/2 equation: 



(z+9)/3=(z-9)/2

We move all terms to the left:

(z+9)/3-((z-9)/2)=0

We calculate fractions


z/()+(-((z-9)*3)/()=0



We calculate terms in parentheses: +(-((z-9)*3)/(), so:

-((z-9)*3)/(

We multiply all the terms by the denominator


-((z-9)*3)



We calculate terms in parentheses: -((z-9)*3), so:

(z-9)*3

We multiply parentheses

3z-27

Back to the equation:

-(3z-27)



We get rid of parentheses

-3z+27

Back to the equation:

+(-3z+27)



We get rid of parentheses

z/()-3z+27=0

We multiply all the terms by the denominator


z-3z*()+27*()=0

We add all the numbers together, and all the variables

z-3z*()=0

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