(3b-4)6=3(b-2)

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Solution for (3b-4)6=3(b-2) equation: 



(3b-4)6=3(b-2)

We move all terms to the left:

(3b-4)6-(3(b-2))=0

We multiply parentheses

18b-(3(b-2))-24=0



We calculate terms in parentheses: -(3(b-2)), so:

3(b-2)

We multiply parentheses

3b-6

Back to the equation:

-(3b-6)



We get rid of parentheses

18b-3b+6-24=0

We add all the numbers together, and all the variables

15b-18=0

We move all terms containing b to the left, all other terms to the right

15b=18

b=18/15

b=1+1/5

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