(z+5)+5(z+2)=10(z-1)

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Solution for (z+5)+5(z+2)=10(z-1) equation: 



(z+5)+5(z+2)=10(z-1)

We move all terms to the left:

(z+5)+5(z+2)-(10(z-1))=0

We multiply parentheses

(z+5)+5z-(10(z-1))+10=0

We get rid of parentheses

z+5z-(10(z-1))+5+10=0



We calculate terms in parentheses: -(10(z-1)), so:

10(z-1)

We multiply parentheses

10z-10

Back to the equation:

-(10z-10)



We add all the numbers together, and all the variables

6z-(10z-10)+15=0

We get rid of parentheses

6z-10z+10+15=0

We add all the numbers together, and all the variables

-4z+25=0

We move all terms containing z to the left, all other terms to the right

-4z=-25

z=-25/-4

z=6+1/4

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