(y/6)+(y/5)=(6/7)

Solution for (y/6)+(y/5)=(6/7) equation:

(y/6)+(y/5)=(6/7)

We move all terms to the left:

(y/6)+(y/5)-((6/7))=0

We add all the numbers together, and all the variables

(+y/6)+(+y/5)-((+6/7))=0

We get rid of parentheses

y/6+y/5-((+6/7))=0

We calculate fractions


245y^2/()+294y^2/()+()/()=0

We add all the numbers together, and all the variables

245y^2/()+294y^2/()+1=0

We multiply all the terms by the denominator


245y^2+294y^2+1*()=0

We add all the numbers together, and all the variables

539y^2=0

a = 539; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·539·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{1078}=0$