(y+8)(y+29)=0

Solution for (y+8)(y+29)=0 equation:

(y+8)(y+29)=0

We multiply parentheses ..

(+y^2+29y+8y+232)=0

We get rid of parentheses

y^2+29y+8y+232=0

We add all the numbers together, and all the variables

y^2+37y+232=0

a = 1; b = 37; c = +232;
Δ = b2-4ac
Δ = 372-4·1·232
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-21}{2*1}=\frac{-58}{2}
=-29
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+21}{2*1}=\frac{-16}{2}
=-8
$