4(b+3)+2b=3(b-11)

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Solution for 4(b+3)+2b=3(b-11) equation: 



4(b+3)+2b=3(b-11)

We move all terms to the left:

4(b+3)+2b-(3(b-11))=0

We add all the numbers together, and all the variables

2b+4(b+3)-(3(b-11))=0

We multiply parentheses

2b+4b-(3(b-11))+12=0



We calculate terms in parentheses: -(3(b-11)), so:

3(b-11)

We multiply parentheses

3b-33

Back to the equation:

-(3b-33)



We add all the numbers together, and all the variables

6b-(3b-33)+12=0

We get rid of parentheses

6b-3b+33+12=0

We add all the numbers together, and all the variables

3b+45=0

We move all terms containing b to the left, all other terms to the right

3b=-45

b=-45/3

b=-15

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