(y+7)(y-3)=(y-1)(y+3)

Solution for (y+7)(y-3)=(y-1)(y+3) equation:

(y+7)(y-3)=(y-1)(y+3)

We move all terms to the left:

(y+7)(y-3)-((y-1)(y+3))=0

We multiply parentheses ..

(+y^2-3y+7y-21)-((y-1)(y+3))=0


We calculate terms in parentheses: -((y-1)(y+3)), so:

(y-1)(y+3)

We multiply parentheses ..

(+y^2+3y-1y-3)

We get rid of parentheses

y^2+3y-1y-3

We add all the numbers together, and all the variables

y^2+2y-3

Back to the equation:

-(y^2+2y-3)


We get rid of parentheses

y^2-y^2-3y+7y-2y-21+3=0

We add all the numbers together, and all the variables

2y-18=0

We move all terms containing y to the left, all other terms to the right

2y=18

y=18/2

y=9