(n+9)(n+1)=(n+6)(n+3)

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Solution for (n+9)(n+1)=(n+6)(n+3) equation: 



(n+9)(n+1)=(n+6)(n+3)

We move all terms to the left:

(n+9)(n+1)-((n+6)(n+3))=0

We multiply parentheses ..

(+n^2+n+9n+9)-((n+6)(n+3))=0



We calculate terms in parentheses: -((n+6)(n+3)), so:

(n+6)(n+3)

We multiply parentheses ..

(+n^2+3n+6n+18)

We get rid of parentheses

n^2+3n+6n+18

We add all the numbers together, and all the variables

n^2+9n+18

Back to the equation:

-(n^2+9n+18)



We get rid of parentheses

n^2-n^2+n+9n-9n+9-18=0

We add all the numbers together, and all the variables

n-9=0

We move all terms containing n to the left, all other terms to the right

n=9

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